Question

Maximum or Minimum. Domain and range of
y=x^2-4x+4

Answer 1

`y=x^2-4x+4\\\\a=1;\ b=-4;\ c=4\\\\a > 0\ then\ minimum:\\\\(-b)/(2a)=(-(-4))/(2\cdot1)=(4)/(2)=2\\\\y_(min)=2^2-4\cdot2+4=4-8+4=0\\\\\\domain:x\in\mathbb{R}\\\\\\range:y\in\left<0;\ \infty\right)`