Question

What is the answer for 6r^2-10r-24

Answer 1

`6r^2-10r-24 =0\\ \\a=6, \ b= -10, \ c= -24 \\ \\ \Delta =b^2-4ac = (-10)^2 -4\cdot6\cdot (-24) = 100+576 = 676 \\ \\ r_(1)=(-b-√(\Delta ))/(2a)=(10-√(676))/(2\cdot 6 )=( 10-26)/(12)= (-16)/(12)=- (4)/(3) \\ \\r_(2)=(-b+√(\Delta ))/(2a)= (10+√(676))/(2\cdot 6 )=( 10+26)/(12)= (36)/(12)=3\\ \\ 6r^2-10r-24 = 6(r+(4)/(3))(r-3)=(6r+8)(r-3)\\ \\ \\ Answer : \ 6r^2-10r-24 =(6r-8)(r-3)`