Question

How do you solve x^2 plus 16x plus 63=0?

Answer 1

`x^2+ 16x + 63=0 \\ \\a=1, \ b=16 , \ c=63 \\ \\ \Delta =b^2-4ac =16^2 -4\cdot1\cdot 63 = 256 -252 = 4 \\ \\x_(1)=(-b-\Delta )/(2a)=(-16-√(4))/(2 )=(-16-2)/(2)=-(-18)/(2)=-9 \\ \\x_(2)=(-b+\Delta )/(2a)=(-16+√(4))/(2 )=(-16+2)/(2)=-(-14)/(2)=-7 \\ \\ \\Answer : \ x= -7 \ \ or \ \ x= -9`