Question

There are two bags containing only purple and white marbles.Bag A has 6 purple marbles and 4 white marbles.Bag B has 8 purple marbles and 8 white marbles.A marble is randomly chosen from each bag.List these events from least likely to most likely.Event 1: choosing a red marble from Bag A.Event 2: choosing a purple marble from Bag A.Event 3: choosing a white marble from Bag B.Event 4: choosing a purple or white marble from Bag B.Least likelyMost likelyEvent (1)EventEvent |Event

Answer 1

Given:

There are two bags containing only purple and white marbles.

Bag A has 6 purple marbles and 4 white marbles.

so, the probability of choosing purple = 0.6

and the probability of choosing white = 0.4

And Bag B has 8 purple marbles and 8 white marbles.

So, the probability of choosing purple = 0.5

And the probability of choosing white = 0.5

Now, we will find the probability of the following events:

Event 1: choosing a red marble from Bag A.

There are no red colors in the bags

So, the probability will be = 0

Event 2: choosing a purple marble from Bag A.

the probability of choosing purple = 0.6

Event 3: choosing a white marble from Bag B.

the probability of choosing white = 0.5

Event 4: Choose a purple or white marble from Bag B.

So, all the marbles are purple or white

so, the probability = 1

So, the events from least likely to most likely will be as follows:

Event 1

Event 3

Event 2

Event 4