Question

Calculate the mass of water produced when 7.14g of butane reacts with excess oxygen

Answer 1

First of all you need a balanced equation:

2(C4H10) + 11(O2) ---> 10 (H2O) +8 (CO2)
Then, you convert the unit :


`7.14 g C4H10` x
`(1mole C4H10)/(58gC4H10)`×
`(10mole H2O)/(2mole C4H10)`×
`(18g H2O)/(1moleH2O)`

The answer should be 11.1g

( I'm not 100% sure about it though)