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Triangular Prism:


\sf~V=(1)/(2)*~l*~w*~h


\sf~V=(1)/(2)*7*3*3


\sf~V=3.5*3*3


\sf~V=10.5*3


\sf~V=31.5

Break the Trapezoidal Prism into a rectangular prism with side measurements of 12, 18, and 6 and into a triangular prism with measurements of 6, 16, and 12.

Rectangular Prism:


\sf~V=lwh


\sf~V=(12)(18)(6)

Multiply all 3 numbers together:


\sf~V=1296

Now find the volume of the triangular prism:


\sf~V=(1)/(2)lwh


\sf~V=(1)/(2)(6)(16)(12)

Multiply all 4 numbers:


\sf~V=576

Add the two volumes together:


\sf1296+576=1872

Now we have to get rid of the area inside.

It's two rectangles both with lengths of 12 and widths of 6.


\sf~A=lw


\sf~A=(12)(6)


\sf~A=72

Multiply by 2 then subtract from the total volume we got:


\sf~72*2 = 144

Subtract it:


\sf1872-144=1728
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