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What is the point-slope form of the equation of a line that passes through the point (6, −8) and has a slope of −2?
A.y+8=2(x-6)

B.y+8=-2(x-6)

C.y-6=-2(x-8)

D.y-8=-2(x+6)

2 Answers

2 votes
Point slope form is:

\sf {y - y_1 = m(x - x_1)}

Where
\sf{(x_1,y_1)} is the point and
\sf{m} is the slope.

So from your question:


\sf{ x_1 = 6}

\sf{y_1 = -8}

\sf{m = -2}

Plug them into the equation for point slope form:


\sf {y - y_1 = m(x - x_1)}

Becomes when you plug it in:


\sf{y-(-8) = -2(x - 6)}

And when you subtract a negative that becomes addition so:


\sf{y+ 8 = -2(x - 6)}

And that would correlate to answer choice
\sf{\boxed{B}}
User Nnnn
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7.7k points
0 votes
y - y1 = m(x - x1)

Where 'y1' is the y-value of the point, 'x1' is the x-value of the point, and 'm' is the slope.

So in this case:

y1 = -8
x1 = 6
m = -2

Plug them in:

y - (-8) = -2(x - 6)

or

y + 8 = -2(x - 6)
User Lecko
by
8.6k points

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