Question

Write an equation of a circle whose center is (-3,2) and whose diameter is 10

Answer 1

`(x-x_1)^2+(y-y_1)^2=r^2\\ (x_1,y_1) - \text{ center}\\\\ r=\frac{\text{ diameter}}{2}=(10)/(2)=5\\\\ (x-(-3))^2+(y-2)^2=5^2\\ \boxed{(x+3)^2+(y-2)^2=25}`

Answer 2

`The\ equation\ of\ a\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ coordinates\ of\ the\ cener;\ r-the\ radius\\-------------------------------\\The\ center\ (-3;\ 2)\to a=-3;\ b=2\\a\ diameter\ d=2r\ therefore\ r=(1)/(2)d\to r=(1)/(2)\cdot10=5\\\\Answer:\\\boxed{(x-(-3))^2+(y-2)^2=5^2}\to\boxed{(x+3)^2+(y-2)^2=25}`