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Factor completely: 3x^2 – 21x + 30 A. 3(x – 2)(x – 5) B. (3x – 2)(x – 15) C. 2(x – 3)(x – 10) D. (x – 2)(x – 5)
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Factor completely: 3x^2 – 21x + 30

A. 3(x – 2)(x – 5)
B. (3x – 2)(x – 15)
C. 2(x – 3)(x – 10)
D. (x – 2)(x – 5)

User Talentedmrjones
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2 Answers

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a because 3(x^2-7x+10)
3(x-2)(x-5)

User Jincy
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5 votes
The answer is going to be A.

You first factor 3 out getting x^2-7x+10

Then you factor that so (x-2)(x-5) then tack that 3 onto the end so 3(x-2)(x-5)
User Fdermishin
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