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19 votes
19 votes
Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to the sun is 65°,how long is the shadow to the nearest tenth of afoot?20 feet6509.3 feet13.2 feet17.2 feet21.1 feet

Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to-example-1
Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to-example-1
Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to-example-2
User Jon Tirsen
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3.3k points

1 Answer

25 votes
25 votes

The triangle formed by the system in the question is shown below:

The length of the shadow is represented by x.

We can use the Tangent Trigonometric ratio to solve for x.

The ratio is given as


\tan \theta=\frac{\text{opp}}{\text{adj}}

From the diagram above, we have the following parameters:


\begin{gathered} \theta=65 \\ \text{opp }=20 \\ \text{adj }=x \end{gathered}

Hence, we can substitute as


\tan 65=(20)/(x)

Solving for x, we have


\begin{gathered} 2.145=(20)/(x) \\ \therefore \\ x=(20)/(2.145) \\ x=9.3\text{ feet} \end{gathered}

The correct answer is the FIRST OPTION (9.3 feet).

Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to-example-1
User Ordnungswidrig
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3.1k points