Question

Toni measured the height of her bedroom doorway with a measuring tape. She measured the height as 171 cm. The doorway’s actual height is 182.8 cm.

What is the percent error in Toni’s measurement? Round to the nearest tenth of a percent, if necessary.

A.
0.12%


B.
6.5%



C.
6.9%


D.
11.8%

Answer 1

First, subtract the two numbers.


`\sf182.8-171=11.8`

Now divide this to the actual measurement.


`\sf11.8/182.8=0.0645514223`

Multiply by 100:


`\sf0.0645514223*100=6.45514223`

So the percent error is approximately
`\sf6.5\%`