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Solving linear system, substitution 20x-30y=-50 x+2y=1 HELP PLEASE
asked
May 28, 2016
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Solving linear system, substitution
20x-30y=-50
x+2y=1
HELP PLEASE
Mathematics
high-school
Darkhydro
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1
Answer
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20x - 30y = -50 ⇒ 20x - 30y = -50
x + 2y = -1 ⇒
20x + 40y = -20
-70y
=
-30
-70 -70
y = ³/₇
20x - 30(³/₇) = -50
20x - 12⁶/₇ = -50
+ 12⁶/₇ + 12⁶/₇
20x
=
47¹/₇
20
20
x = 2⁷/₂₀
(x, y) = (2⁷/₂₀, ³/₇)
Ttekin
answered
Jun 2, 2016
by
Ttekin
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