The way I would do it is the following.
Multiply x+5y=-3 by 3, making it 3x+15y=-9. Now, you can subtract the one equation from the other So, if you wrote it properly, it would look like
3x+15y=-9
-(3x-2y=8)
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=>17y=-17 which means y=-1. Now you can plug in y=-1 in the first equation, x+5y=-3, showing that x-5=-3, meaning x=2.
This is how I would do it. Of course, one could also solve for x in terms of y in the first equation, solving that x=-3-5y, and then substituting that into the second equation. I hope this is helpful.