Question

Solve with completing the square method:
6x²-7x+2=0 and  ax²+bx+c=0

Answer 1

`6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^(2)-4ac = (-7)^(2)-4*6*2=49-48=1 \\ \\x_(1)=(-b-√(\Delta ))/(2a) =(7-√(1))/(2*6)=(7-1)/(12) =(6)/(12)= (1)/( 2)\\ \\x_(2)=(-b+√(\Delta ))/(2a) =(7+√(1))/(2*6)=(7+1)/(12) =(8)/(12)= (2)/( 3)`