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A weather balloon has a volume of 52.5 liters at a temperature of 295 K. The balloon is released and rises to an altitude where the temperature is 252 K. How does the temperature change described affect the gas particle motion?

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Answer:

Gas particle motion will drop as the temperature reaches 252 K

Step-by-step explanation:

Initial temperature T1 = 295 K

Final temperature, T2 = 252 K

The kinetic energy of the gas particles is related to the temperature via the following equation:


KE = (3)/(2) kT

where k = Boltzmann constant

Based on the above equation we can write:


(KE(1))/(KE(2)) = (T1)/(T2) = (295)/(252) = 1.17

KE(1) = 1.17KE(2)

This implies that the kinetic energy is lower at T2 and therefore the gas particles will slow down as the balloon rises.

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