Question

use coordinate methods (for example, distance formida, midpoint formida, or shape forudia) to provethese triangles are similar,B721-1N-1F-2+-3-E

Answer 1

`\begin{gathered} (BF)/(BC)=(BE)/(BD),\text{ hence the triangles are similar} \\ U\sin g\text{ distance formula we can find the value of }BF,\text{ BC, BE and BD} \\ B(1,7),\text{ }F(-5,-2),E(4,-8),C(-1,4)andD(2,2)\text{ } \\ BF=\sqrt[]{(1-(-5))^2+(7-(-2))^2} \\ BF=√(6^2+9^2) \\ BF=10.81 \\ BE=√((1-4)^2+(7-(-8))^2) \\ BE=√(3^2+15^2) \\ BE=15.3 \\ BC=√((1-(-1))^2+(7-4)^2) \\ BC=√(2^2+3^2) \\ BC=3.6 \\ BD=√((1-2)^2+(7-2)^2) \\ BD=4.69 \\ (BF)/(BC)=(BE)/(BD)=(10.81)/(3.6)=(15.3)/(4.69)\approx3,\text{ hence the triangles are similar} \end{gathered}`