Question

HELP PLEASE

Which equation is graphed here?

A. y-3=-2/3(x+1)

B. y-4=-3/2(x+2)

C. y-1=-3/2(x+3)

D. y+1=-2/3(x+3)

Answer 1

B
it is a easy question. just find two points and find a good function
like these points: (0,1) . (2, -2)

Answer 2

Option B is correct.

`y-4=-(3)/(2)(x+2)`

Explanation:

Point slope form:

The equation of straight line is given by:

`y-y_1=m(x-x_1)` ......[1] where m is the slope and a point
`(x_1, y_1)` lies on the coordinate plane

From the given graph:

Consider two points i.e,

(-2, 4) and (2, -2)

Calculate slope:

Slope(m) is given by;

`m = (y_2-y_1)/(x_2-x_1)`

Substitute the given points we have;

`m = (-2-4)/(2-(-2)) = -(6)/(4) = -(3)/(2)`

Now, substitute the value of m and (-2, 4) in [1] we have;

`y-4=-(3)/(2)(x-(-2))`

or

`y-4=-(3)/(2)(x+2)`

Therefore, the equation is graphed here is
`y-4=-(3)/(2)(x+2)`