{(v + 3)}^(2) + 4 =0I don't understand

Christiaan Adams asked Oct 16, 2023

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44 votes

${(v + 3)}^(2) + 4 =0$ I don't understand

Christiaan Adams asked Oct 16, 2023

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26 votes

we will solve the following equation

$(v+3)=\pm\sqrt[]{-4}$
$(v+3)=\pm2i$
$v=-3\pm2i$

Davislor answered Oct 21, 2023

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