Question

The circle below is centered at (-3, 2) and has a radius of 3. What is its

equation?
A. (x-3)2 +(- 2)2 = 9
B. (x+3)2 + (y-2)2 = 3
C. (x+3)2 + (y-2)2 = 9
D. (x-3)2 + (y-2)2 = 3

Answer 1

C

Explanation:

The equation is (x-a)^2 + (y-b)^2 = r^2

(x+3)^2+(y-2)^2 = 9