1 Answer

Penny Liu · Answer 1 · 2023-04-22T06:05:13+0000

Given:

Initial velocity = 24.3 m/s

Angle = 38.5°

Let's find how far away the ball landed.

To find the distance, apply the projectile motion formula below:

$R=(V^2\sin (2\theta))/(g)$

Where:

g = 9.8 m/s^2

V = 23.4 m/s

θ = 38.5°

Thus, we have:

$R=(23.4^2\ast\sin (2\ast38.5))/(9.8)$

Solving further:

$\begin{gathered} R=(547.56\sin(77))/(9.8) \\ \\ R=(547.56\cdot0.97437006)/(9.8) \\ \\ R=(533.52607267)/(9.8) \\ \\ R=54.4\text{ m} \end{gathered}$

Therefore, the footabll lands 54.4 meters away

ANSWER:

54.4 m

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