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32 votes
32 votes
factor each of the following by factoring out the GCF
2x {}^(7) - 10x {}^(5) + 20x {}^(4)
6x {}^(8) + 12x {}^(10)
32x {}^(7) + 24x {}^(4) - 8x {}^(3)MORE NOTES FOR QUESTION 2
6y - 24 \\ answer = (y - 4)
3a + 12 \\ anwser = 3(a + 4)

factor each of the following by factoring out the GCF 2x {}^(7) - 10x {}^(5) + 20x-example-1
User Griffosx
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1 Answer

12 votes
12 votes

4x^3-12x^2+8x=4x\cdot x^2-4x\cdot3x+4x\cdot2=4x(x^2-3x+2)

For the second one


50y^6-25y^7=25y^6\cdot2-25y^6\cdot y=25y^6(2-y)

for the third one


32x^7+24x^5-8x^3=8x^3\cdot4x^4-8x^3\cdot3x^2-8x^3\cdot1=8x^3(4x^4+3x^2-1)

The greatest common factor for the first one is 4x

for the second one is 25y^6

and for the third one is 8x^3

User Suever
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