Question

Y=-2x +13x-2y=5how to solve the system equations algebraically?

Answer 1

The given equations are:

`\begin{gathered} y=-2x+1 \\ 3x-2y=5 \end{gathered}`

So from the first equation, we have the value for y. Now we can substitute that value in the second equation for y. We have,

`\begin{gathered} 3x-2(-2x+1)=5 \\ 3x+4x-2=5 \\ 7x=5+2 \\ 7x=7 \\ x=(7)/(7)=1 \end{gathered}`

Now we can substitute the value of x in the equation for y,

`y=-2*1+1=-2+1=-1`

Hence, x = 1 and y = -1.