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the ratio of kinetic energy to the potential energy of a certain object of mass m at a height of 40 m above ground level is 2:1. What is the speed of the object at the point? Use g=10 m/s^2 A.)20 m/s B.
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the ratio of kinetic energy to the potential energy of a certain object of mass m at a height of 40 m above ground level is 2:1. What is the speed of the object at the point? Use g=10 m/s^2 A.)20 m/s B.)40 m/s C.)30 m/s D.) 10 m/s

User Mpalanco
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I believe it is A) 2(1/2mv^2)=mgh <===cross out masses
2(1/2V^2)=gh

Solve for V
User Ananda
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