Question

Complete each equation and write a balanced net ionic equation for each reaction. Identify the spectator ions in each reaction. Use Solubility Rules.5. BaCl2(aq) + K2SO4 (aq)—--→ 6. Na2S(aq) + Cd(NO3)2(aq) —--→7. Al(s) + H2SO4(aq) —--→8. HCl(aq) + Ba(OH)2 —--→

Answer 1

Step-by-step explanation:

Given:

`5.BaCl_(2(aq))+K_2SO_(4(aq))\rightarrow`

The complete equation is:

`BaCl_(2(aq))+K_2SO_(4(aq))\rightarrow BaSO_(4(s))+2KCl_((aq))`

The balanced ionic equation for the reaction is:

`Ba^(2+)+2Cl^-+2K^++SO^(2-)_{4^{}}\rightarrow BaSO^{}_{4(s)^{}}+2K^++2Cl^-`

The BaSO₄ is an insoluble solid, so it will not dissociate into ions.

The spectator ions in the reaction are ions that are present at both the reactant side and the product side.

Hence, the spectator ions are:

`Cl^-,and\text{ }K^+`

Therefore, the balanced net ionic equation is:

`Ba^(2+)_((aq))+SO^(2-)_{4_((aq))^{}}\rightarrow BaSO^{}_{4(s)^{}}`