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If the sum of three consecutive even integers is 192, what is the first of the three integers?

If the sum of three consecutive even integers is 192, what is the first of the three integers?
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4 votes
If the sum of three consecutive even integers is 192, what is the first of the three integers?

User Tahesha
by
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1 Answer

5 votes
smallest:x-2
middle:x
biggest:x+2

smallest+middle=biggest=(x-2)+(x)+(x+2)=3x
3x=192->3x/3=192/3->x=64

smallest: 64-2=62
User Rohit Azad Malik
by
7.4k points
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