What is the inverse function of g(x)=1/x-2

asked Jun 6, 2016 96.9k views

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1 vote

Assuming it's
g(x)=(1)/(x-2)

$y=(1)/(x-2)\\ x-2=(1)/(y)\\ x=(1)/(y)+2\\ g^(-1)(x)=(1)/(x)+2$

Erickg answered Jun 12, 2016

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