Tossing a number cube numbered from 1 to 6 and getting an Evan number that is greater than of equal to 2

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asked Jan 28, 2016 21.0k views

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Fenil Patel · Answer 1 · 2016-01-31T20:24:26+0000

even numbers on die: 2,4,6
odd numbers on die: 1,3,5
3+3=6 -> 6 numbers in total
3/6 chance because there are 3 even numbers. This would round to 1/2, so 1/2 a chance the die will roll an even number.

Tossing a number cube numbered from 1 to 6 and getting an Evan number that is greater than of equal to 2

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