Find the vertex of F(x)=2(x+10)^2+20

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asked Jul 12, 2016 167k views

2 votes

Find the vertex of F(x)=2(x+10)^2+20

Mathematics
high-school

Royce Feng asked

by Royce Feng

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1 Answer

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$f(x)=2(x+10)^2+20\\f(x)=2(x^2+20x+100)+20\\f(x)=2x^2+40x+200+20\\f(x)=2x^2+40x+220\\f'(x)=4x+40=0\\4x=-40\\x=-10\\\\f(-10)=2((-10)+10)^2+20\\f(-10)=2(0)^2+20\\f(-10)=20\\(-10,20)$

The vertex of f(x) is at (-10, 20).

Nate Kohari answered Jul 16, 2016

by Nate Kohari

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