Question

Rewrite the equation in vertex form: y=x^2-8x+13

Answer 1

`vertex\ form:y=a(x-p)^2+q\\\\wher\ p=(-b)/(2a)\ and\ q=f(p)\\\\\\y=x^2-8x+13\\a=1;\ b=-8;\ c=13\\\\p=(-(-8))/(2\cdot1)=(8)/(2)=4\\\\q=f(4)=4^2-8\cdot4+13=16-32+13=-3\\\\Answer:y=(x-4)^2-3`