Question

Evaluate log (base 9) 27. Can someone explain this one for me so i could do some tasks on my own?

Answer 1

You would use some properties of the logarithm. First,
`log_927=log_(3^2)27=(1)/(2)log_327`. So, now you have
`log_327` to calculate. It's
`log_33^3=3`, so the final result is
`(1)/(2)*3=(3)/(2)`
Hope it helps.

Answer 2

`log_927=log_93^3=3log_93=3log_9\sqrt9=3log_99^(1)/(2)\\\\=(1)/(2)\cdot3log_99=(3)/(2)`