Find the 168th term of arithmetic sequence {a_{n}, n = 1, 2, 3, . . .} with common ifference d = 1.5 and first term a_{1} = 2.

asked Jan 5, 2015 138k views

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$a_1=2;\ d=1.5\\\\a_n=a_1+(n-1)d\\\\a_n=2+(n-1)\cdot1.5=2+1.5n-1.5=0.5+1.5n\\\\a_(168)=0.5+1.5\cdot168=0.5+252=252.5$

Hemant Rao answered Jan 8, 2015

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