Question

F(x) = tan 2x , f'(x) = ....

Answer 1

using the chain rule :
`[\tan(2x)]'=(2x)'\tan'(2x)=(2)/(\cos^2(2x))`

Answer 2

`f(x)=\tan 2x\\ f'(x)=\sec^2 2x\cdot2=2\sec^2 2x`