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a gas had a volume of 50L and a temperature of 650k. if the temperature increased to 2600k, what would be the volume be?
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a gas had a volume of 50L and a temperature of 650k. if the temperature increased to 2600k, what would be the volume be?

User Audrey Sobgou Zebaze
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2 Answers

5 votes
Charles' Law: V1 = V2 V2 = V1T2 V2 = (50L)(2600K) = 200L
T1 T2 T1 (650K)
User Kinggs
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Assuming it's a perfect gas, we have PV=nRT hence V and T are proportional. T increased by 2600/650=4 times hence the volume will be 4 times bigger, which is 200L
User Odwori
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7.8k points
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