Question

How do I factorise 2t^2 + 5t +2

Answer 1

`2t^2+5t+2\\\\a=2;\ b=5;\ c=2\\\\\Delta=b^2-4ac;\ if\ \Delta > 0\ then\ t_1=(-b-\sqrt\Delta)/(2a)\ and\ t_2=(-b+\sqrt\Delta)/(2a)\\\\\Delta=5^2-4\cdot2\cdot2=25-16=9;\ \sqrt\Delta=\sqrt9=3\\\\t_1=(-5-3)/(2\cdot2)=(-8)/(4)=-2;\ t_2=(-5+3)/(2\cdot2)=(-2)/(4)=-(1)/(2)\\\\2t^2+5t+2=2(x+2)(x+(1)/(2))`