Question

Find the 8th term of geometric sequence {a_{n}, n = 1, 2, 3, . . .} with common ratio r = 0.5 and first term a_{1} = 2.

Answer 1

`a_n=a_1\cdot q^(n-`1)\\\\a_1=2;\ q=0.5=(1)/(2)\\\\\\a_8=a_1\cdot q^(8-1)=a_1\cdot q^7\\\\a_8=2\cdot\left((1)/(2)\right)^7=2\cdot(1)/(2^7)=2\cdot(1)/(128)=(1)/(64)\\\\\\Answer:a_8=(1)/(64)`