Question

The graph shows the distances traveled by two toy trains.

A third train travels 15 feet in 3 seconds.

How does the third train compare with Train 1 and Train 2?



A.
The third train is slower than both Train 1 and Train 2.

B.
The third train is faster than both Train 1 and Train 2.

C.
The third train is faster than Train 1 but slower than Train 2.

D.
The third train is faster than Train 2 but slower than Train 1.

Answer 1

From the graph ...

-- Train-1 travels more than 15 feet in 3 seconds.

-- Train-2 travels less than 15 feet in 3 seconds.

So, if Train-3 travels exactly 15 feet in 3 seconds,
then Train-3 is faster than #2 but slower than #1 .

Answer 2

Answer:D. The third train is faster than Train 2 but slower than Train 1.

Explanation:

Since, If the speed of one object is greater than that of other object then we can say that one object is faster than other object.

Here, the speed of third train = 15/3=5 feet/sec ( because speed = distance/time)

And, according to the given graph the speed of train 1= 30/5=6 feet/sec ( by taking the approximate value of x and y by the graph)

While, the speed of train 2= 20/5= 4 feet/sec

Thus, we can say that, Speed of train 1>Speed of train 3> Speed of train 2

Therefore, Only Option D is correct.