Question

Trying to get the solution set of w= square root 8w-12?

Answer 1

`D:8w-12\geq0\\ D:8w\geq12\\ D:w\geq(12)/(8)\\ D:w\geq(3)/(2)\\\\ w=√(8w-12)\\ w^2=8w-12\\ w^2-8w+12=0\\ w^2-2w-6w+12=0\\ w(w-2)-6(w-2)=0\\ (w-6)(w-2)=0\\ w=6 \vee w=2`

Answer 2

Square both sides :

w^2=8w-12 hence w^2-8w+12=0

Discriminant : 64-4*12=16=4^2 hence the solutions could be (8-4)/2, (8+4)/2 which are w=2 and w=6