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Given: BD is a diameter

m 1 = 100°
m BC = 30°
m AC =

60
110
200

Given: BD is a diameter m 1 = 100° m BC = 30° m AC = 60 110 200-example-1
User Sad
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1 Answer

10 votes

Answer:

110°

Explanation:


m\angle 1 + m\angle 2 = 180\degree

(linear pair angles)


100\degree + m\angle 2 = 180\degree


m\angle 2 = 180\degree- 100\degree


m\angle 2 = 80\degree


\because m\widehat {AB} =m\angle 2

(Measure of the minor arc is equal to the corresponding central angle)


\therefore m\widehat {AB} = 80\degree


\because m\widehat {AC} =m\widehat {AB} +m\widehat {BC}

(By arc sum property)


\therefore m\widehat {AC} = 80\degree+30\degree


\huge \red {\boxed {\therefore m\widehat {AC} = 110\degree}}

User Cweinberger
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