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(cosx-cscx)/(sinx-secx)=cotx prove this
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(cosx-cscx)/(sinx-secx)=cotx prove this

User NorthCat
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(\cos-1/\sin)/(\sin-1/\cos)=(\cos\sin-1)/(\sin\cos-1)\cdot(\cos)/(\sin)=\cot
User Dloewen
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