Question

X^2+5x-104=0 solve quadratic equations

Answer 1

You first have to factor and get (x-8)(x+13)=o and set them equal to zero x-8=0 x=8 x+13=0 x=-13

Answer 2

`x^2+5x-104=0\\\\a=1;\ b=5;\ c=-104\\\\\Delta=b^2-4ac;\ if\ \Delta > 0\ then\ x_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\\\\\Delta=5^2-4\cdot1\cdot(-104)=25+416=441;\ \sqrt\Delta=√(441)=21\\\\x_1=(-5-21)/(2\cdot1)=(-26)/(2)=-13;\ x_2=(-5+21)/(2\cdot1)=(16)/(2)=8\\\\Answer:x=-13\ or\ x=8.`