Question

How do i solve x^2-11x+14=0 using the quadratic formula

Answer 1

x² - 11x + 14 = 0
x = -(-11) +/- √((-11)² - 4(1)(14))
2(1)
x = 11 +/- √(121 - 56)
2
x = 11 +/- √(65)
2
x = 11 +/- 8.062257748
2
x = 11 + 8.062257748 x = 11 - 8.062257748
2 2
x = 19.062257748 x = 2.937742252
2 2
x = 1.906225775 x = 1.468871126

Answer 2

`x^2-11x+14=0 \\ \\ a=1 \\ b=-11 \\ c=14 \\ b^2-4ac=(-11)^2-4 * 1 * 14=121-56=65 \\ x=(-b \pm √(b^2-4ac))/(2a)=(-(-11) \pm √(65))/(2 * 1)=(11 \pm √(65))/(2) \\ \boxed{x=(11 - √(65))/(2) \hbox{ or } x=(11+√(65))/(2)}`