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Solve for: A = a b= Round to the nearest tenth.

Solve for: A = a b= Round to the nearest tenth.-example-1
User Kevinadi
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1 Answer

17 votes
17 votes

We have the following triangle:

First, we start from the fact that we have an internal angle of 72 degrees and a right angle i.e. a 90-degree angle.

Second, having two internal angles, we solve and find the last internal angle.


180-90-72=18

Third, we find "a" and "b" with the law of sines, the equation of this law is:


(a)/(\sin(A))=(b)/(\sin (B))=(c)/(sn(C))

Where we have these values:


\begin{gathered} a=a \\ b=b \\ c=11 \\ \sin (A)=\sin (18) \\ \sin (B)=\sin (72) \\ \sin (C)=\sin (90)=1 \end{gathered}

Now we solve "a"


\begin{gathered} (a)/(\sin (18))=(11)/(\sin (90)) \\ a=11\cdot\sin (18) \\ a=3.3991\cong3.4 \end{gathered}

Now we solve "b"


\begin{gathered} (b)/(\sin (72))=(11)/(\sin (90)) \\ b=11\cdot\sin (72) \\ b=10.4646\cong10.46 \end{gathered}

In conclusion, the answers are approximate:


\begin{gathered} a\cong3.4 \\ b\cong10.46 \end{gathered}

Solve for: A = a b= Round to the nearest tenth.-example-1
User Jestan Nirojan
by
3.2k points