Question

2x+3y=12 how do I solve for x and y

Answer 1

2x + 3y = 12
2x - 2x + 3y = 12 - 2x
3y = 12 - 2x
3 3
y = 4 - 2/3x
2x + 3(4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
-12 -12
0x = 0
0 0
x = 0
2(0) + 3y = 12
0 + 3y = 12
-0 -0
3y = 12
3 3
y = 4
(x, y) = (0, 4)

Answer 2

2x+3y= 12

To solve for the x intercept, y=0

2x+3(0)= 12

2x= 12

Divide both sides by 2

2x/2x= 12/2x

X= 6

So:(6,0)

To solve for y intercept, x=0

2(0)+3y= 12

3y= 12

Divide both sides by 3

3y/3y= 12/3

Y= 4

So: (0,4)