49.2k views
4 votes
Which system of equations can be used to solve the following problem?

Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $115, and 33 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets.


A.3c+5a=33
a + c=115


B. 3a+5c=33
a + c=115

C. 5c+3a=115
c + a=33

D. 3c+5a=115
a +c

User Lotz
by
7.2k points

1 Answer

1 vote
the answer is C. 5c+3a=115
c + a=33
if each child's ticket is $3 and there are 4 child tickets sold, then the total is 3×4 if each child ticket is $3 and there are "c" child tickets sold, the total is 3c for the childs tickets
User Smolchanovsky
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.