Question

What is the intersection point of 2x+19y=3 and 1x-3=7y

Answer 1

2x + 19y = 3 ⇒ 2x + 19y = 3 ⇒ 2x + 19y = 3
1x - 3 = 7y ⇒ 1x - 7y = 3 ⇒ 2x + 14y = 6
5y = -3
5 5
y = -3/5
2x + 19(-3/5) = 3
2x - 11 2/5 = 3
+11 2/5 +11 2/5
2x = 14 2/5
2 2
x = 7 1/5
(x, y) = (7 1/5, -3/5)

Answer 2

`2x+19y=3\\19y=-2x+3\\y=-(2)/(19)x+(3)/(19)\\\\x-3=7y\\y=(1)/(7)x-(3)/(7)\\\\-(2)/(19)x+(3)/(19)=(1)/(7)x-(3)/(7)\\-(14)/(133)x+(21)/(133)=(19)/(133)x-(57)/(133)\\(78)/(133)=(33)/(133)x\\(78)/(33)=x\\x=(26)/(11)\\\\((26)/(11))-3=7y\\((26)/(11))-(33)/(11)=7y\\(-7)/(11)=7y\\-11=y`

(26/11, -11)