Find the center and radius of x^2+y^2=9

asked Nov 16, 2016 32.0k views

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$(x-x_1)^2+(y-y_1)^2=r^2\\ \text{center}=(x_1,y_1)\\\\ x^2+y^2=9\\ (x-0)^2+(y-0)^2=9\\ \text{center}=(0,0)\\ r=\sqrt9=3$

ItsMeInMiami answered Nov 19, 2016

6.5k points

5 votes

$x^2+y^2=9\Leftrightarrow (x-0)^2+(y-0)^2=3^2$ hence the center is (0,0) and the radius is 3

Iohans answered Nov 20, 2016

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