Question

Solving by completing the square
X square+4x-4=0

Answer 1

`x^2+4x-4=0 \\ x^2+4x+4-8=0\\ (x+2)^2=8\\ x+2=-\sqrt8 \vee x+2=\sqrt8\\ x=-2-2\sqrt2 \vee x=-2+2\sqrt2`

Answer 2

`x^2+4x-4=0 \\ x^2+4x+4-4-4=0 \\ (x+2)^2-8=0 \\ (x+2)^2=8 \\ x+2=\pm √(8) \\ x+2=\pm √(4 * 2) \\ x+2=\pm2√(2) \\ x+2=-2√(2) \ \lor \ x+2=2√(2) \\ x=-2√(2)-2 \ \lor \ x=2√(2)-2 \\ \boxed{x=-2√(2)-2 \hbox{ or } x=2√(2)-2}`