Question

How do you solve 4b^2+8b+7=4 using the quadratic formula

Answer 1

b= { (-8) ± Sqrt(8^2)-4(4x(3) ) } / 2(4)
b={ (-8±) (Sqrt(16) ) } / 8
b=(-8+4)/8 and b=(-8-4)/8
b= -4/8 and b=-12/8
b=-1/2 and b=-3/2
b={-1/2, -3/2} is the solution.
Click image for formula.
Sqrt means Square Root.

Answer 2

`4b^2+8b+7=4\\ 4b^2+8b+3=0\\\\ x=(-b\pm√(b^2-4ac))/(2a)\\\\ x=(-8\pm√(8^2-4\cdot4\cdot3))/(2\cdot4)\\ x=(-8\pm√(64-48))/(8)\\ x=(-8\pm√(16))/(8)\\ x=(-8\pm4)/(8)\\ x=(-2\pm1)/(2)\\ x=(-1)/(2 )\vee x=(-3)/(2)\\ x=-(1)/(2 )\vee x=-(3)/(2)`