Question

An empty beaker weighs 39.09 g

A)when completely filled with water, the breaker and its contents have a total mass of 388.15 g. what volume does the beaker hold? use d=1.00 g/mL as the density of the water.

2)how much would the beaker and its contents weigh if it was completely filled with mercury? the density of mercury is d=13.5 g/mL.

Answer 1

The beaker has a volume of 349.06 mL when filled with water. If filled with mercury, taking into account its density of 13.5 g/mL, the beaker and its contents would weigh 4751.4 g.

Step-by-step explanation:

To calculate the volume the beaker can hold, we use the mass of the filled beaker and subtract the empty beaker's mass. The difference gives us the mass of the water, which we can then divide by the density of water (1.00 g/mL) to find the volume.

For water:
Total mass of the filled beaker - Mass of the empty beaker = Mass of the water
388.15 g - 39.09 g = 349.06 g
Since density (d) of water = 1.00 g/mL, Volume (V) of water = Mass (m) of water / Density (d) of water
Volume = 349.06 g / 1.00 g/mL = 349.06 mL

For mercury:
To find out how much the beaker would weigh if filled with mercury, we use the volume we just calculated and multiply it by the density of mercury (13.5 g/mL).
Mass of mercury = Volume × Density of mercury = 349.06 mL × 13.5 g/mL = 4712.31 g
Total mass of the beaker filled with mercury = Mass of the empty beaker + Mass of mercury = 39.09 g + 4712.31 g = 4751.4 g

Answer 2

To work out the volume of something from its density, use the compound measures triangle: mass over density and volume. To find volume that the beaker holds, divide the mass by the density. V = (388.15 - 39.09)/1. V = 349.06g/cm3. To find the weight of the beaker and the contents, first work out the weight (mass) of the mercury, with this formula: mass = d x v. M = 13.5 x 349.06. M = 4712.31. Then add on the weight of the beaker (39.09g). The total weight is 4751.40g.