Question

if the quadratic formula is used to find the roots of the equation x^2-6x-19=0, what is the correct roots

Answer 1

`x^2-6x-19=0\\ x^2-6x+9-28=0\\ (x-3)^2=28\\ x-3=√(28) \vee x-3=-√(28)\\ x=3+2\sqrt7 \vee x=3-2\sqrt7`

Answer 2

`x^(2) -6x-19=0 \\ \\discriminant= b^(2)-4ac=> \\ 36-(-76)=76+36=112 \\ \\ -b- √(disc.)/2a=>6- √(112)/2 \\ =>6- 4√(7)/2 \\ =3- 2√(7) \\ \\ -b +√(disc)/2a=6+4 √(7) /2 \\ =3+ 2√(7) \\ \\ Solution\: set:(3- 2√(7) ,3+ 2√(7) ) \\ \\ \framebox[1.1\width]{Good Luck!!} \par`